return to table of content

A breakthrough towards the Riemann hypothesis

cvoss
20 replies
1d2h

What are your opinions of all the theorems that rely on RH as an excluded middle?

Constructivists reject exmid, saying instead that a proof of "A or B" requires you to have in hand a proof of A or a proof of B. And nobody yet has a proof of RH nor a proof of ~RH. This is important in so-called incomplete logical systems, where some theorems are neither provable nor disprovable, and, therefore, exmid is an inadmissible axiom.

nerdponx
18 replies
1d2h

Aren't those sort of different things? I thought the whole point of provability was that it was distinct from truth.

floxy
15 replies
1d2h

How do you know something is true if you don't have a proof? It all depends on you views on the philosophy of mathematics. Are there "true" statements that don't have proofs? Some say yes, there are platonic ideas that are true, even if they aren't provable. Others say, "what does it even mean to say something is true, if there is no proof. What you really have is a conjecture."

xrisk
8 replies
1d2h

Didn’t Gödel show that in most useful logical systems there are true statements that cannot be proved?

xavxav
5 replies
1d

Indeed, the first incompleteness theorem tells us that any logical framework which can express Peano arithmetic must necessarily contain true (resp. false) facts for which no (resp. counter) proof can be given.

Sometimes you can prove that no proof exists about a specific sentence (that's what his incompleteness proof does), and I think you could extend this technique to construct sentences where no proof exists of whether it has a proof, etc...

strbean
1 replies
21h59m

any logical framework which can express Peano arithmetic

(with a finite list of axioms)

jrvidal
0 replies
21h1m

I think the precise pre-condition is that the theory should be recursive, which means either a finite list of axioms _or_ a computable check to determine whether a given formula is an axiom.

zajio1am
0 replies
5h32m

must necessarily contain true (resp. false) facts for which no (resp. counter) proof can be given

This formulation misses the important aspect that whether the statement is 'true' is not absolute property (outside logical truths). We can consider truthfulness of a statement in a specific structure or in a specific theory.

E.g. a statement can be undecidable in Peano arithmetic (a theory) while true in natural numbers (a structure, model of Peano arithmetic), but that just means there is a different structure, different model of Peano arithmetic in which this statement is false.

lisper
0 replies
19h57m

the first incompleteness theorem tells us that any logical framework which can express Peano arithmetic must necessarily contain true (resp. false) facts for which no (resp. counter) proof can be given.

Not quite. Any logical framework which can express Peano arithmetic must necessarily contain true facts for which no proof can be given within PA. The proof of Godel's theorem itself is a (constructive!) proof of the truth of such a statement. It's just that Godel's proof cannot be rendered in PA, but even that is contingent on the assumption that PA consistent, which also cannot be proven within PA if PA is in fact consistent. In order to prove any of these things you need to transcend PA somehow.

Filligree
0 replies
1d

The latter would be an axiom. A disproof would be a proof that there is no proof, so if you’d proven that no proof exists one way or the other then you’ve proven it can’t be disproven _or_ proven.

Which means you’ve hit a branch in mathematics. You can assume it to be either true or false, and you’ll get new results based on that; both branches are equally valid.

hnfong
0 replies
1h38m

No he showed either there are true statements that cannot be proved, OR the system is inconsistent...

lisper
4 replies
1d2h

There is another possibility: it could be an arbitrary choice, as in the case of the parallel postulate, the axiom of choice, and non-standard models of the Peano axioms.

btilly
3 replies
20h30m

According to logicians, it always is an arbitrary choice. But we have a second-order notion of what "finite integer" should mean. And within that notion the idea might be false.

Here's how that plays out. Suppose that the RH cannot be proved or disproved from ZF. (It turns out that choice cannot matter for all theorems in number theory, so ZF is enough.) That means that there is a model of ZF in which RH is true. Every model of ZF contains a finite calculation for any non-trivial zero of the Riemann function. (The word "finite" is doing some heavy lifting here - it is a second order concept.) That calculation must work out the same in all models. Therefore every finite nontrivial zero has complex part 0.5. Therefore RH is actually true of the standard model of the integers. Therefore every model of ZF where RH is false, is non-standard.

The truth of RH is therefore independent of ZF. But it's true in our second order notion of what the integers are.

lisper
2 replies
19h53m

The word "finite" is doing some heavy lifting here - it is a second order concept.

Sorry, you're going to have to explain that to me. The word "finite" has only one meaning AFAIK and on that definition it is definitely not the case that "every model of ZF contains a finite calculation for any non-trivial zero of the Riemann function." I don't even know what it means for ZF to "contain a calculation." The concept of calculation (at least the one that I'm familiar with) comes from computability theory, not number theory.

lupire
1 replies
17h9m

"finite" means what you think it means: a program that halts.

Look at Peano Axioms:

https://en.m.wikipedia.org/wiki/Peano_axioms

The Induction axiom allows us to write finite proofs of otherwise infinite facts, like every positive integer has a predecessor.

Without it, you'd be stuck with finitism (since only a finite number of numbers can be constructed in finite time, there is only a finite number of numbers.)

lisper
0 replies
15h57m

I think you're confusing PA with computability theory and Turing machines. "Program" is not a thing in PA.

lupire
0 replies
17h18m

Probability is relative to an axiom systems.

A more powerful system can prove statements that are true but not provable in a weaker system.

For example "This sentence is not provable." (Godel's statement, written informally) is true, but not provable, in first order arithmetic logic.

https://en.m.wikipedia.org/wiki/Diagonal_lemma

In constructivist mathematics, proving that a statement is not false is not a proof that it is true. Non-constructivist mathematics, on the other hand, has the axiom, for all P: P or not-P, also stated as not-not-P implies P.

zajio1am
0 replies
5h30m

The whole point of provability is that it is purely syntactic process that could be verified in finite time. Ideally it would be the same as truth, but there are some caveats.

alex_smart
0 replies
1d2h

Not according to constructivists.

riemann12
0 replies
12h44m

I’ve heard this argument:

If RH is unprovable one way or another, then certainly no counterexample can exist to the RH otherwise you could find it and prove the RH to be false.

Hence if RH is unprovable, it must be true. I suppose this uses logic outside the logical system that RH operates in.

jl6
18 replies
1d4h

Without intending to take anything away at all from the work of the researchers, I think “breakthrough” might just be overselling it.

They have improved a bound but I can’t tell that their method will open up a plausible path to a full proof. It feels like we’ve managed to increase the top speed of a car from 200mph to 227mph, but are no closer to understanding how the engine works.

gus_massa
9 replies
1d4h

The author of the post is Terence Tao that is the best live mathematician. If he says it's a "breakthrough", it's a breakthrough. (Anyway, I agree that if you are not in this research area, it's still an internal result that you can safetly ignore.)

Also, in the last years he was leading a few project to crowsource improvements after breakthroughs in other conjetures. I'm too far from this area to be sure, but if he sees there is a chance to improve this, I expect him to launch a new one.

From the article:

but they do a number of clever and unexpected maneuvers

If he post something like that about me, I'd frame it an hang it in the wall.

nybsjytm
7 replies
1d2h

The author of the post is Terence Tao that is the best live mathematician. If he says it's a "breakthrough", it's a breakthrough.

I think it's pretty silly to say that Tao is the best living mathematician, but even if he were I don't think that this would be a useful way to think about things.

btilly
4 replies
21h15m

No matter what you think, best living mathematician is what other mathematicians say about him.

But I'll humor you. How would you prefer we say things?

- Highest IQ on record.

- One of only 3 people to score over 700 on the Math SAT before he was 8. He had the highest score of the three with 760.

- At ages 10, 11, and 12 he set the record for winning Bronze, Silver, and Gold respectively in the International Math Olympiad. After that he lost interest.

- PHD from Princeton at 21.

- Full professor at UCLA at 24. This is a record.

- He is a respected leader in at least a half-dozen areas of mathematics. He regularly publishes in many more. It is unusual for a mathematician to have significant publications in 2 areas.

- Wikipedia lists 28 major prizes for him. Excepting Australian of the Year in 2022, all are major mathematics prizes. No other mathematician comes close.

- Once you exclude junk journals, Tao publishes papers faster than any other mathematician. And his are all good.

- Tao's papers show up in the popular press more often than the next 3 mathematicians combined.

And so on.

At what point is there a better way to think about this than, "best live mathematician"?

(And yeah, until I began noticing Tao, I would have also thought that a silly way to think...)

fishtockos
2 replies
20h46m

The idea that Tao has accomplished more than, say, Serre because the latter, who won the Fields medal at 27, only received his PhD at 25 and his bachelor's at 22 while the former received his PhD at 21 and his bachelor's at 16 is so absurd that it can be refuted merely by alluding to it.

Your other points are similar.

btilly
1 replies
20h16m

Serre is indeed a top mathematician. (I'm actually surprised to find out that he's still alive!)

At this point Tao only has 3/4 his number of publications, similar numbers of textbooks, a similar number of awards (using https://mathshistory.st-andrews.ac.uk/Biographies/Serre/ to count awards), and so on. I'd count Tao as having more of what I see as major breakthroughs, but that is subjective. But then again, Tao is half of Serre's age.

Yeah. I still think it is fair to put Tao in the same tier as Euler, Gauss and Hilbert.

auntienomen
0 replies
17h23m

Time will tell.

nybsjytm
0 replies
13h32m

Sorry, I think this style of hagiography is completely goofy, there's nothing else to say about it. And I'm sure it's not even true that he has the "highest IQ on record."

To make a claim like "greatest living mathematician" it would be more appropriate to talk about his actual research accomplishments and how they compare to canonical figures like Gromov, Milnor, Serre, Smale, Yau, among many younger counterparts.

But, personally, I think defending any such claim for any particular person is kind of a juvenile exercise. I am a mathematician and among the slight minority of mathematicians I know who would take the question seriously, a minority of them would select Tao. Which of course isn't to say that he isn't universally considered a top mathematician.

kadoban
0 replies
22h45m

Yeah, random people on HN are much better judges of importance of mathematical results.

gus_massa
0 replies
21h56m

I think it's pretty silly to say that Tao is the best living mathematician

I agree. I was going to write "one of the best" or "probably the best" or something like that. It's like discussing if Messi or Maradona were the best football players. [1]. Anyway, all three of them are quite good.

but even if he were I don't think that this would be a useful way to think about things.

I also agree. It's just and argument by authority. For a decition that would change the lives of millons of persons and has a lot of subtle tradeoff and unknown unknowns, I'd ask for a better justification and evidence. But deciding if this is a breakthrough or not, may only change the lives of a few graduate students and a few grown up mathematicians, so I'm happy to take the word of Tao.

[1] Hi from Argentina!

jlarcombe
0 replies
1d3h

Well, the two authors of the paper he's talking about are also amongst the foremost mathematicians in the world today. James Maynard won the Fields medal a couple of years ago. So they've probably got used to approbation from the likes of Terence Tao. Nonetheless, exciting!

QuesnayJr
2 replies
1d3h

It probably doesn't open up a path to a full proof, simply because Guth and Maynard are excellent mathematicians, and they wouldn't have given away their approach yet if they thought they could prove the full thing.

It's still important because there hasn't been much new evidence in years whether the conjecture is true or false. Now we have some new evidence that it's true.

lupire
0 replies
16h52m

That's not how math community generally works.

Everyone knows what the important idea of a proof is. Publishing the work that grates a new field of mathematics that leads to a proof is not worse than toiling away privately (for longer!).

Gregory Perelman, the only Millennium Prize winner, declined the prize because he refused to accept credit for Richard S Hamilton's foundational work.

JadeNB
0 replies
1d1h

I don't think that's really conclusive; surely they've taken it as far as they think they can in a reasonable amount of time, but (1) they've no real need to be secretive--why not share it as soon as there's a concrete result?, and (2) sometimes the inventor of a technique can be too used to the old way of thinking to use their new technique to its full potential, and it takes less experienced eyes on it.

math_dandy
1 replies
1d4h

It may take many breakthroughs to yield a proof of the Riemann Hypothesis. Progress on a notoriously hard problem through introduction of innovative new ideas can certainly qualify as a breakthrough, imo. Naturally, the importance of the breakthrough will be judged by what can be built upon it.

fishtockos
0 replies
1d1h

This is clever application of existing ideas, not the sort of new idea which is needed. No one can really imagine what sort of machinery will need to be built to prove the RH. A proof is completely outside the realm of speculation at this point.

magnio
0 replies
1d4h

Change that to CPU performance in 2023 and you got a breakthrough as well.

btilly
0 replies
1d4h

When you've been stuck for 80 years, any improvement at all seems like a big deal.

But more importantly, a new idea like this often points the way to variations that may also create improvement. Therefore as other researchers pile on, we may see this bound come down further.

So yes, it is like a wall in a maze was breached, and there is the opportunity to go further. And it is fair to call that a breakthrough. Of course you're still charging into a maze, and further progress is far from guaranteed.

abetusk
0 replies
1d4h

I'm no expert and I don't like engaging in arguments to authority but Terrence Tao is one of the leading mathematicians of our age, akin to Erdos. When he's excited about a result, that should be a high signal indicator that it's worth paying attention.

In terms of the result itself, as Tao explains:

... making the first substantial improvement to a classical 1940 ...

Meaning, it's been 80 years since any progress has been made on this front (bounds of zeros of the Riemann zeta function).

I would make the argument that it's not so much making a top speed car from 200mph to 227mph but discovering an engine that uses gasoline instead of steam.

Presumably the methods used in the paper might be able to be extended or refined to get better results.

vsnf
15 replies
1d3h

What are the practical implications of a conclusion of the hypothesis, in either direction?

throw_pm23
10 replies
1d3h

This is pure math, so not much, at least directly or immediately.

But I find it amusing how this argument always comes up and how it goes back millenia.

  A student of Plato (428 B.C. -- 348 B.C.) once asked the great master, "What practical uses do these theorems serve? What is to be gained from them?" Plato's answer was immediate and peremptory. He turned to one of his slaves and said, "Give this young man an obol [a small Greek coin] so that he may feel that he has gained something from my teachings. Then expel him."

vsnf
9 replies
1d3h

I didn’t mean to imply that it needed to be useful. I just hear about the hypothesis a lot and I wonder what the immediate knock-on effects would be. Does it unlock other theoretical work, are there other proofs that work or don’t work depending on it, etc. And if it has an effect on something real or tangible that’s even better.

moi2388
5 replies
1d2h

In principle a proof of the Riemann Hypothesis could give you information about the distribution of primes and could possible make it easier to test for primality, in the worst case breaking modern encryption.

But that’s a lot of what ifs away.

Ar-Curunir
2 replies
1d2h

There is no known result that says RH being true breaks modern encryption; if there was, the cryptanalysts would assume RH and try to break it anyway.

IsTom
1 replies
21h35m

Not RH being true, but that the proof itself would require discovering and proving something of high interest as an intermediate step.

Ar-Curunir
0 replies
20h53m

Perhaps, but it’s not clear that would be cryptographically relevant still.

Ar-Curunir
1 replies
20h52m

Testing primality doesn’t break encryption; we already test for primarily on a daily basis very efficiently

moi2388
0 replies
12h4m

My apologies, that is not what I meant. I meant that the proof might break encryption. Again, might. As response to a list of possible real-world implications as the reader asked for.

kristopolous
2 replies
18h47m

These things are kind of like landing on the moon. The act of actually walking on the moon is fairly symbolic and ultimately the more important things were the achievements required to get there.

What the current state of the problem demonstrates is there's some unknown quantity of cutting edge work required that has yet to be done; maybe there's a cunning conceptual error in some field that has somehow missed everyone's eye or maybe there's an entirely new mathematical concept or tool which makes the problem straight-forward, but nobody has "invented it" yet.

One day, the time we are in right now will be "150 years ago". Contemporaries of any time think all fundamental things have been exhausted and discovered for whatever reason. It was as true in 1874 as 2024.

And they've always been wrong. Doesn't mean you or I can get there. It'll take some brilliant individual or team years of sweat equity, skill and profound luck but one day, right now too will be 150 years ago and people will look back on us as we look back on 1874 mathematics.

Problems like Riemann is how we forge ahead.

lupire
1 replies
16h59m

There's another possibility: that everything discoverable by humans as been discovered.

Before long, AIs and organizations will be claiming to prove things that no human has the capacity to verify with reasonable confidence, or humans will run or of capacity or make progress. We just had the 1000 page Geometric Langlands proof.

kristopolous
0 replies
11h51m

"everything discoverable by humans as been discovered" again, this claim is made by every generation like clockwork, going back as long as humans have been making claims that can be recorded.

I trust it's as wrong now as it always has been.

bonzini
1 replies
1d3h

https://en.wikipedia.org/wiki/Riemann_hypothesis#Consequence... lists several theorems that have been proved conditionally on the Riemann hypothesis being true. The most notable is probably the Goldbach conjecture, though that requires the generalized Riemann hypothesis.

Maxatar
0 replies
1d2h

It's a weak form of the Goldbach conjecture not the actual Goldbach conjecture itself. The weak form also has a proof that does not depend on the Riemann hypothesis.

math_dandy
0 replies
1d2h

Many heuristics in cryptanalysis rely on heuristics widely believed about the distribution of prime numbers. If RH is proved, some of these heuristics would become theorems.

It would not, however, give practicing cryptanalysts new tools since belief in RH (and some even stronger conjectures!) are already baked in to the current toolbox.

eigenvalue
0 replies
1d1h

With these longstanding open problems, it's often not the result itself that is useful so much as the new techniques or the unification of previously unrelated branches of math that are invented/discovered to prove the result. Fermat's last theorem by itself didn't really lead to much new math, but the proof of it certainly did (and showed previously unknown relationships between modular forms and elliptic curves, and opened up new areas of research in number theory, algebraic geometry, and arithmetic geometry).

nomilk
13 replies
1d2h

Also curious about the potential significance of a proof. The article is vague:

(primes) are important for securing encrypted transmissions sent over the internet. And importantly, a multitude of mathematical papers take the Riemann hypothesis as a given. If this foundational assumption were proved correct, “many results that are believed to be true will be known to be true,” says mathematician Ken Ono of Emory University in Atlanta. “It’s a kind of mathematical oracle.”

Are there some obvious, known applications where a RH proof would have immediate practical effects? (beyond satisfaction and 'slightly better encryption').

dgacmu
10 replies
1d2h

If we knew that the extended Riemann hypothesis was true, we could use the Miller test for deterministic primality testing in log(n)^4; the AKS test, which doesn't depend on RH, is lg(n)^6.

Do we care? Not for most applications -- doing a bunch of randomized Miller-Rabin tests is fine for most practical purposes. But it would be really nice to have a faster deterministic algorithm around. AKS isn't practical for anything; miller... Miiiiiggghtt be.

olddustytrail
5 replies
1d2h

Then why not just assume it's true and if something breaks, hey, you might just have disproved it?

aj7
2 replies
1d1h

What if an airliner or a spacecraft or a self- driving car or a surgical robot breaks?

pfdietz
0 replies
5h51m

The randomized algorithm doesn't need to be perfect, it just needs to present a failure probability << the failure rate from other causes. And it can easily do that, since the failure probability goes down exponentially with the number of iterations of the test.

olddustytrail
0 replies
1d1h

They already do. Was this supposed to be an enlightening question?

dgacmu
1 replies
1d

Because for practical things we have a faster solution that might also be wrong occasionally (randomized testing). There's no benefit to using any of the known deterministic tests if they're not truly deterministic. The speed gap vs randomized is huge.

olddustytrail
0 replies
22h45m

Then it seems it wouldn't be better to use the deterministic test ever. Just use the randomised test and accept the failure rate.

tzs
3 replies
1d

To put some numbers on it, assume a civilization of 1 trillion people, with each person using 1 000 things that needs a large prime, and those 1 000 things need to generate a new prime 1 000 times a second.

The most conservative bound on the chance that a random single Miller-Rabin test will say that a composite number is prime is 1/4.

Using that bound, if that civilization used Miller-Rabin with 48 random Miller-Rabin tests to find primes they would get a composite falsely identified as a prime about once every 60 000 years.

If they used 64 tests they would have one false positive about ever 258 trillion years. That's past the point when all stars in the universe have run out of fuel.

Now assume that every star in the universe has a similar civilization. If everyone uses 96 Miller-Rabin tests there will be a false positive about once per 24 billion years.

As I said that is using a false positive rate of 1/4, which is very conservative. There's a paper [1], "Average Case Error Estimates For the Strong Prime Test" by Damgard, Landrock, and Pomerance that gives several bounds.

Their bounds are in terms of k, the number of bits of the odd number being tests, and t, the number of random Miller-Rabin tests. They give 4 bounds, for various ranges of k and t:

  (* Valid for k >= 2 *)
  k^2 4^(2-Sqrt[k])

  (* Valid if t = 2, k >= 88 or if 3 <= t <= k/9, k >= 21 *)
  k^(3/2) 2^t t^(-1/2)  4^(2-Sqrt[t k])

  (* Valid for t >= k/9, k >= 21 *)
  7/20 k 2^(-5t) + 1/7 k^(15/4) 2^(-k/2-2t) + 12 k 2^(-k/4-3t)

  (* Valid for t >= k/4, k >= 21 *)
  1/7 k^(15/4) 2^(-k/2-2t)
It is the second one that is most relevant in most situations where you want a large prime and want to do as few tests as possible to get your false positive chances below your acceptable threshold.

Using the hypothetical trillion being civilization with each being needing a million primes a second, here's the expected number of years between that civilization seeing a false positive using the second bound above, for k = 64 and t 2 through 5:

  2 3.6 x 10^26
  3 7.6 x 10^27
  4 8.5 x 10^28
  5 6.5 x 10^29
The bound gets lower as k increases. If they needed 1024 bit primes that table becomes:

  2 1.5 x 10^45
  3 1.3 x 10^51
  4 1.1 x 10^56
  5 2.1 x 10^60
[1] https://math.dartmouth.edu/~carlp/PDF/paper88.pdf

dgacmu
1 replies
23h32m

Oh, no disagreement. "Practical" really means "practical for math things where you want to guarantee correctness, not just have extremely high confidence". I can't think of any normal use of primes that needs something past what you can do with a bunch of M-R tests.

But we _do_ use a lot of computational power to verify finding particularly interesting primes, etc., so I maintain that it'd be a nice thing to have in our pocket. You never know when you'll find yourself on a deserted island with a powerful computer and need to deterministically prove the primality of a large number. ;)

sdenton4
0 replies
16h20m

Of course, if you end up with an incorrect result due to assuming the Riemann hypothesis, you'll get a fields medal anyway...

tzs
0 replies
14m

Note: the first section, using the conservative estimate, is correct. The second using the tighter bounds is not. I multiplied where I should have divided, leading to an error of a factor or around 10^48 in both tables. E.g., for generating 1024 bit primes with 5 tests the trillion people civilization generating a million primes a second per person would see one error around every 10^12 years, not one ever 10^60 years.

For 64 bit primes they would need to do around 48 tests per prime to get down to a similar error rate.

For

spenczar5
0 replies
1d2h

In the realm of applications, most engineers would say that our confidence in the RH (or more realistically, downstream consequences thereof) is high enough to treat it as true. The proof is, for applications, a formality (albeit a wide-ranging, consequential one!).

More likely, a proof of the Riemann Hypothesis would require new ideas, techniques, and math. It is probable that those devices would have broader reach.

The applications of expansions in math often work that way: as we forge through the jungle, the tools we develop to make our way through are more useful than the destination.

mtlmtlmtlmtl
0 replies
1d1h

Mathematics is sort of strange in this regard in that there's lots of work already done that assumes RH, so many of the consequences of the theorem itself are already worked out. And RH seems to be true on extensive numerical searches(no counterexamples found). So the theorem being true wouldn't be earth-shattering in and of itself.

It's more about the method used to prove the theorem, which might involve novel mathematics. And probably will in this case considering how long it's taking to prove RH. Since this method hasn't been found yet, it's hard to say what the consequences of it might be.

At least that's my layman's understand of it.

adtac
8 replies
1d1h

And only once every four years.

Unfortunately, they award it on the 4n+2 years. As someone born on a 4n+0 year, I’ll have just 38 years, which is too severe a disadvantage for me to stomach, so I didn’t bother with it.

4n+2 people, you have no excuses.

gosub100
4 replies
1d

The margin is too thin, in other words?

manuelmoreale
3 replies
22h55m

What a great reference! Well done.

arrowsmith
2 replies
7h47m

I don't get it.

seanhunter
1 replies
6h19m

Pierre de Fermat wrote his "last theorem" (that no three positive integers a, b, c satisfy a^n + b^n = c^n for integer values of n>2) in the margin of a copy of Diophantus' arithmetica with the comment that "I have a truly marvelous proof which this margin is too thin to contain".

The theorem went unproved for 385 years until Andrew Wiles eventually proved it in 1995, winning the Abel prize (because he was too old to win a Fields medal). Most people think Fermat didn't have a proof - just an intuition - as Wiles' proof uses a bunch of extremely sophisticated and powerful results that came well after Fermat.

The GP's comment is particularly clever because until Wiles, the Riemann hypothesis and Fermat's last theorem were the two most famous unsolved problems in maths, so were often talked about together as being these almost unassailable challenges.

https://en.wikipedia.org/wiki/Fermat%27s_Last_Theorem

manuelmoreale
0 replies
2h9m

Thank you for explaining it way better than I could have done

chongli
1 replies
9h17m

I went over this table of Fields Medal winners [1] and the 4n+2 people have won 28% of the awards. However, 33% of the awards were won by 4n+3 people but only 17% were won by 4n+0 people.

So your hypothesis does seem to bear out: people born on 4n+0 years are at a significant disadvantage for winning a Fields medal.

[1] https://stats.areppim.com/listes/list_fieldsxmedal.htm

hyperbovine
0 replies
6h2m

Error bars please.

lupire
0 replies
17h34m

The 2022 Fields medal winners were born in 1983, 1984, 1985, and 1987 (Maynard).

Sniffnoy
1 replies
21h8m

Yes, I don't think the Fields medal was intended as the "Nobel prize of mathematics", but since it was the biggest award that existed it got promoted as such despite its inequivalence. More recently there's the Abel prize, which tries to be a more direct Nobel prize analogue, but of course the Fields medal has a multi-decade head start in terms of promotion...

aleph_minus_one
0 replies
18h58m

Nobel Prize (and Abel Prize and Wolf Prize) are for the lifetime achievement, i.e. the scientific contributions that lead to the prize might be from decades ago.

ks2048
0 replies
19h5m

Maynard's videos on Numberphile are great. Like Tao, he seems to be able to explain things clearly to non-experts - I think another sign of greatness.

wing-_-nuts
9 replies
1d3h

Can I get a ELI!M[Not a mathematician]?

nhatcher
2 replies
1d3h

One of the most important open problems in mathematics is called the Riemann hypothesis. It states that the solutions of a certain equation `zeta(z)=0` are all of a particular type. Almost every living mathematician has tried to solve it at some point in their lives. The implications of the hypothesis are deep for the theory of numbers, for instance for the distribution of prime numbers.

In a recent paper some mathematicians claim they have put some stronger bounds on where those solutions can be. In this link Terrence Tao, one of the most acclaimed mathematicians alive speaks very highly about the paper.

IMHO, this is probably not of huge interest to not mathematicians just yet. It is an extremely technical result. And pending further review it might very well be wrong or incomplete.

There are lots of places you can read about the Riemann Hypothesis, its implications and its attempts to solve it.

chii
1 replies
14h59m

As for why the Riemann Hypothesis itself is interesting, it is because this zeta function seems to have information about the primes inside it.

The eye opener for me is when a video about it connected the idea of the zeta function to how you might create a square wave by adding successive sine waves (of higher and higher frequency).

Imagine a function (call it `prime_count`), which gives you the number of prime numbers below it's argument.

If you tried to plot this function on a graph, it will look like a series of jaggard steps - a jump when you reach a new prime number. It turns out, if you rewrite the zeta function and decompose it (into it's infinitely many zeros - akin to doing a "taylor series" expansion for other functions), you will find that the more zeros you use, the closer you will get to a jaggard graph.

This video is really good at giving a visual explanation : https://youtu.be/e4kOh7qlsM4?t=594

seanhunter
0 replies
6h3m

The eye opener for me is when a video about it connected the idea of the zeta function to how you might create a square wave by adding successive sine waves (of higher and higher frequency).

The process of taking an arbitrary waveform and approximating it by adding together a series of sine and/or cosine waves with different amplitudes etc is called a Fourier transform. That is what Terrence Tao is talking about when he mentions trying this approach using Fourier analysis himself. [1] Fourier transforms are used all over the place, eg the discrete cosine transform (DCT) is part of JPEG, MP3 etc.

[1] https://en.wikipedia.org/wiki/Fourier_analysis

senderista
1 replies
22h47m

_Prime Obsession_ is a good book-length intro to the RH (and to Riemann himself) that doesn't assume any math background.

cgh
0 replies
18h15m

Seconded, a great read and quite accessible. History chapters are interspersed with more mathematical ones. I would say having some basic math background is helpful but not totally necessary.

chx
1 replies
1d3h

Remember Indiana Jones and the Last Crusade? They are not in the chamber yet but they did disarm one of the traps in the temple.

fishtockos
0 replies
1d1h

More like Indy avoided drowning in the boat race scene (which I recall happening very early in the movie)

QuesnayJr
0 replies
1d3h

We have an approximate expression of how many prime numbers there are less than N, as N gets larger. If the Riemann hypothesis is true, then we know that the errors in this approximation are nice and small, which would allow us to prove many other approximate results. (There are many results of the form "If the Riemann hypothesis is true, then...")

idlewords
9 replies
1d4h

Trying to imagine what it must feel like to have Terence Tao summarize your argument while mentioning that he'd tried something similar but failed.

"The arguments are largely Fourier analytic in nature. The first few steps are standard, and many analytic number theorists, including myself, who have attempted to break the Ingham bound, will recognize them; but they do a number of clever and unexpected maneuvers."

chx
2 replies
1d3h

Yes but it's Terence Tao. I mean, the set of living mathematicians is not well ordered on greatness but if it were, Terence Tao would be fairly close to the upper limit.

alkyon
0 replies
1d3h

Maynard won a Fields medal, Tao is of course in the elite, but so is JM.

Ar-Curunir
0 replies
1d3h

Maynard is a Fields Medallist, so is also one of the strongest mathematicians around.

random3
1 replies
1d2h

It must feel like meritocracy. Like when ranking, particularly in strict order, is not the norm - so Terrence Tao doesn't see himself "on top" of anything. Moreover it must imply some solid grounding and a good understanding of how someone's actions are not expected to be correlated with their reputation. This is especially the case where getting the results is a personal or strictly team effort, not a popularity contest.

It can be unexpeted for anyone that's operating in the regular business, corporate, VC and general academic landscape where politics rule while meritocracy is a feel good motivator while popularity is the real coin.

Ar-Curunir
0 replies
20h55m

Tao and Maynard are both academics…

ants_everywhere
1 replies
18h38m

I haven't met him personally, but Tao's writing is very humble and very kind. He talks openly about trying things and not having them work out. And he writes in general a lot about tools and their limitations. I definitely recommend reading his blog.

simple_quest_9
0 replies
13h21m

I find that mathematicians tend to have the smallest egos -- eccentric as they may be. I think it's because the difficulty of mathematics reminds one of their fallibility.

In school, I typically found the math and physics teachers to be humbler than the others. Not always, but, I couldn't help but notice that trend.

nybsjytm
0 replies
1d2h

It's perfectly common for a mathematician to successfully use a technique where another top mathematician tried and failed.

amirhirsch
8 replies
1d1h

I made this visualization of the zeta function in javascript, it is infinitely zoomable, and you can play around with parameters: https://amirhirsch.com/zeta/index.html

It might help you understand why the hypothesis is probably true. It renders the partial sums and traces the path of zeta.

In my rendering, I include all partial sums up to an automatically computed "N-critical" which is when the phase difference between two summands is less than pi (nyquist limit!), after which the behavior of the partial sums is monotonic. The clusters are like alias modes that go back and forth when the instantaneous frequency of the summands is between kpi and (k+1)pi, and the random walk section is where you only have one point per alias-mode. The green lines highlight a symmetry of the partial sums, where the clusters maintain symmetry with the random walk section, this symmetry is summarized pretty well in this paper: https://arxiv.org/pdf/1507.07631

3abiton
3 replies
23h32m

Any good easily digestible sources on this topic?

arrowsmith
0 replies
7h48m

That video was really great - thanks for sharing.

WoahNoun
0 replies
13h58m

Prime Obsession by John Derbyshire

nyc111
0 replies
11h28m

What is the actual formula you are using to plot the graph?

md224
0 replies
16h46m

Aw man, yours is way cooler than mine: https://matt-diamond.com/zeta.html

Still, it's funny to see how many people have attempted this! It's a fun programming exercise with a nice result.

amirhirsch
0 replies
1d

I formed an intuitive signal processing interpretation of the Riemann Hypothesis many years ago, which I'll try to summarize briefly here. You can think of the Zeta function as a log-time sampler -- zeta(s) is the Laplace transform of sum(delta(t-ln n)) which samples at time t=(ln n) for integers n>0, a rapidly increasing sample rate. You can imagine this as an impulse response coming from a black box, and the impulse response can either be finite in energy or a power signal depending on the real parameter.

If you suppose that the energy sum(|1/s|^2) is finite (ie real(s) > 1/2), then the Riemann Hypothesis implies that the sum is non-zero. It is akin to saying that the logarithmic sampler cannot destroy information without being plugged-in.

ganzuul
5 replies
1d6h

This improves modeling of long-tail distributions? How far off am I here?

gus_massa
2 replies
1d4h

If the complex number is x+iy:

They had a good bound of the long-tail distribution when x>=3/5=0.6. Now someone extended that result to x>=13/25=0.52. (The long term objective is to prove a stronger version for x>1/2=.5.)

konstantinua00
1 replies
1d

it's different

affected distribution is always x>3/4, both before and after

what's measured is upper bound on number of zeroes <y, relative to y

it was <y^(3/5), now it's <y^(13/25)

it says nothing about absence of zeroes, but the density result already affects prime distributions

gus_massa
0 replies
22h5m

My bad. Thanks for the correction.

lupire
1 replies
1d4h

Can you be more specific? This is a result about a specific approximately known distribution.

ganzuul
0 replies
1d3h

Excuse me I meant the related heavy-tailed distributions, which show up in dragon king theory.

I'm wondering if this result indicates we have a new method to eke out important signals from noise that otherwise get smoothed out.

greenthrow
4 replies
1d2h

This comments section is very oddly filled with people who don't actually understand the subject matter but want to sound smart, and then accomplish the opposite. Let go of your insecurities people, it's ok to not understand some things and be open about it. Everyone doesn't understand more things than they do.

Maxatar
1 replies
22h38m

Apart from one flagged comment I find the comments to be quite profound and interesting, we even have a cool visualization demo of the Riemann zeta function:

https://news.ycombinator.com/item?id=40571995#40576767

Your comment is rather condescending and kind of feels like a form of projection rather than a meaningful contribution.

greenthrow
0 replies
21h24m

The comment you link is two hours newer than mine. I also didn't say it's only that type of comment. But when I commented, there were several comments that were just completely off base or bordering on nonsensical due to not understanding the subject. This is a toxic phenomenon that we don't really address, and I thought was interesting to highlight and also share a positive message to those afflicted by the malady of insecurity. You can choose to read in whatever you want, but that was (pretty obviously) my intent.

tucnak
0 replies
11h56m

Oh, I knew your username sounded familiar. Mister Smarty-Pansy-Cynical-McLoser back at it again!

CyberDildonics
0 replies
21h21m

This comments section is very oddly filled with people who don't actually understand the subject matter but want to sound smart, and then accomplish the opposite.

Just this one?

greekanalyst
4 replies
1d4h

Always amazed by Terence Tao's clarity of thought.

Not only is he one of the greatest mathematical minds alive (if not the greatest), he is also one of the most eloquent writers on mathematics.

Nothing more beautiful than seeing great science being married with great writing.

Even if you don't understand the specifics, you can always get the big picture.

Thank you, Terence!

alexander2002
3 replies
1d3h

Does he have any beginner friendly books on math I saw some clips of his masterclass but I am skeptical of masterclass in general so I am not sure about that

ted_dunning
0 replies
23h49m

His masterclass is substantially better than the average masterclass, particularly for somebody who isn't already an amateur or better mathematician.

empeyot
0 replies
10h23m

His book Analysis I, and potentially also his linear algebra lecture come to mind.

dan-robertson
0 replies
1d2h

He has a blog which has some more elementary posts and some less. But I’m not sure if that would be sufficiently ‘beginner friendly’ for your needs. https://terrytao.wordpress.com/

brcmthrowaway
2 replies
23h13m

Why does the universe require so much grinding for this problem

It makes no sense if the rest of the universe relies upon simple rules

gus_massa
1 replies
21h34m

There are some math problems with that are simple to ask but very difficult to solve. For example

https://en.wikipedia.org/wiki/Four_color_theorem You need a long explanation to reduce the problem to only a thousand of cases, and then you can test the thousand of cases with a computer or write the solution of each case if you are brave enough.

https://en.wikipedia.org/wiki/Fermat%27s_Last_Theorem You replace the original integer numbers with integer complex numbers and get a solution for small n. But for big n you realize some properties of factorization don't work anymore, and then have to write a few books of algebra and then understand the conection with eliptic curves (whatever they are [1]) and modular forms (whatever they are [2]) and then write another book just to prove the tricky part of the theorem.

[1] I studies eliptic surves as a small part of a course, only for two or three weeks. I'm not sure how they are conected with this.

[2] I have no idea what they are.

oulu2006
0 replies
16h24m

[1] neither

[2] neither

:) but I'm glad there are people out there that do!

billforsternz
2 replies
21h23m

I think I read somewhere ("The Music of the Primes" maybe?) that the Riemann Hypothesis says that all zeroes of the Zeta function are on a line in the complex plane, and that although it is unproved, it has been proved all the zeroes are within a narrow strip centred on the line and you can make the strip as arbitrarily narrow as you like. I often wonder if I misunderstood somehow because it seems to me if it is really as I just restated it, well the Riemann Hypothesis is obviously true, that proof is "good enough" for engineering purposes anyway.

gavagai691
1 replies
21h7m

"It has been proved all the zeroes are within a narrow strip centred on the line and you can make the strip as arbitrarily narrow as you like."

Nothing close to this is known.

The nontrivial zeros of zeta lie within the critical strip, i.e., 0 <= Re(s) <= 1 (in analytic number theory, the convention, going back to Riemann's paper is to write a complex variable as s = sigma + it)*. The Riemann Hypothesis states that all zeros of zeta are on the line Re(s) = 1/2. The functional equation implies that the zeros of zeta are symmetric about the line Re(s) = 1/2. Consequently, RH is equivalent to the assertion that zeta has no zeros for Re(s) > 1/2. A "zero-free region" is a region in the critical strip that is known to have no zeros of the Riemann zeta function. RH is equivalent to the assertion that Re(s) > 1/2 is a "zero-free region." The main reason that we care about RH is that RH would give essentially the best possible error term in the prime number theorem (PNT) https://en.wikipedia.org/wiki/Prime_number_theorem. A weaker zero-free region gives a weaker error term in the PNT. The PNT in its weakest, ineffective form is equivalent to the assertion that Re(s) >= 1 is a zero free region (i.e., that there are no zeros on the line Re(s) = 1).

The best-known zero-free region for zeta is the Vinogradov--Korobov zero-free region. This is the best explicit form of Vinogradov--Korobov known today https://arxiv.org/abs/2212.06867 (a slight improvement of https://arxiv.org/abs/1910.08205).

I think your confusion stems from the fact that approximately the reverse of what you said above is true. That is, the best zero-free regions that we know get arbitrarily close to the Re(s) = 1 line (i.e., get increasingly "useless") as the imaginary part tends to infinity. Your statement seems to suggest that the the area we know contains the zeros gets arbitrarily close to the 1/2 line (which would be amazing). In other words, rather than our knowledge being about as close to RH as possible (as you suggested), our knowledge is about as weak as it could be. (See this image: https://commons.wikimedia.org/wiki/File:Zero-free_region_for.... The blue area is the zero-free region.)

* I don't like this convention; why is it s = sigma + it instead of sigma = s + it? Blame Riemann.

billforsternz
0 replies
20h53m

Thank you! I periodically remember this and for years I've been meaning to try to find out for sure whether I had somehow just misunderstood completely. Very pleased to know for sure that I had and that the Riemann Hypothesis remains a genuine mystery.

GalaxyNova
0 replies
20h30m

There's always a relevant xkcd isn't there

samscully
0 replies
1d1h

For anyone looking for an introduction to the Riemann Hypothesis that goes deeper than most videos but is still accessible to someone with a STEM degree I really enjoyed this video series [1] by zetamath.

I understood everything in Profesor Tao's OP up to the part about "controlling a key matrix of phases" so the videos must have taught me something!

[1] https://www.youtube.com/watch?v=oVaSA_b938U&list=PLbaA3qJlbE...

nsoonhui
0 replies
12h33m

Fun fact: one of the author, Larry Guth, is the son of Alan Guth, theoretical physicist of inflation Cosmology fame (https://en.wikipedia.org/wiki/Larry_Guth)

mr-roboto
0 replies
1d3h

Good timing for me. I'm in the middle of listening to "The Humans" by Matt Haig. The story opens after someone proves the Riemann hypothesis.

Havoc
0 replies
18h30m

No idea what any of that means but they’re clearly stoked about it so happy for them